Subject: [xsl] Re: print out the actual node (NEWBIE) From: thomas <thomas.lohbeck@xxxxxx> Date: Mon, 16 Sep 2002 15:16:44 +0200 |
I found a resolution. ugly hack I think...but it works <xsl:value-of select="name(../../../..)"/> <xsl:text>/</xsl:text> <xsl:value-of select="name(../../..)"/> <xsl:text>/</xsl:text> <xsl:value-of select="name(../..)"/> <xsl:text>/</xsl:text> <xsl:value-of select="name(..)"/> <xsl:text>/</xsl:text> <xsl:value-of select="name()"/>
Im having problems with my template and I think somehow its related to the node. Is there a way to print out the actual node I'm in?
<a> <b/> <c> <xsl:value-of select="name()"/> </c> <d/> </a>
prints out only "c" but I need "a/c"
cant find anything.
thanx
le beck
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