RE: [xsl] RE:

["Kirk Allen Evans" <kaevans@xxxxxxxxxxxxx>]

The source is actually the XML file, so it is showing you the correct
listing.  However, you can download a utility add-on for IE that will
allow you to look at the output of the transformation [1].  The utility
is called "Internet Explorer Tools for Validating XML and Viewing XSLT
Output."

[1]
http://msdn.microsoft.com/downloads/sample.asp?url=/msdn-files/027/000/5
43/msdncompositedoc.xml&frame=true


Kirk Allen Evans
http://www.xmlandasp.net
Author, "XML And ASP.NET", New Riders Publishing
http://www.amazon.com/exec/obidos/ASIN/073571200X

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-
> list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of CROFT, MICHAEL
> Sent: Wednesday, September 18, 2002 11:14 AM
> To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'
> Subject: [xsl] RE:
> 
> 		When the browser renders the XML document using my XSLT
> stylesheet, the report displays successfully in the browser, and then
you
> select view source on the browser, it only displays the XML document.
It
> is
> not outputting my html tags.  It is a .xml file, not a .html file.
> 
> 		Mike
> 
> 				-----Original Message-----
> 				From:	David Carlisle
> [mailto:davidc@xxxxxxxxx]
> 				Sent:	Wednesday, September 18, 2002
10:26
> AM
> 				To:	xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> 				Subject:
> 
> 
> 				> 	Does anyone know how to have the
I.E
> 6.0 browser output a
> 				> rendered XML document using XSLT as an
> HTML document.
> 
> 				that's what it does. (What do you mean
by
> "output" though in
> 				the case of a browser?)
> 
> 				>
> xmlns:fo="http://www.w3.org/1999/XSL/Format";>
> 				you don't appear to need to declare the
FO
> namespace in this stylesheet
> 
> 
> 				This isn't needed as it will already be
the
> default as the top level
> 				element is html.
> 						<xsl:output
method="html"/>
> 
> 
> 				David
> 
> 
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