Re: [xsl] How to find parent's-parent's-sibling-sibling name

Subject: Re: [xsl] How to find parent's-parent's-sibling-sibling name
From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx>
Date: Thu, 19 Sep 2002 08:31:50 +0000
And I hope that I am right in what I have mentioned in the Subject line of
this mail ;-)

with what you have asked for, i wud have thot that u need parent's sibling..


Try the following code and let me know if thaz not what you want

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:for-each select="/BehaviourInfo/BehaviourBitmaps/BehaviourBitmapsInfo">
<xsl:value-of select="."/><br/>
<xsl:value-of select="../../Trap/Name"/>
<hr/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>



From: "Satish, L. Gnanendra" <LGnanendra.Satish@xxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: "'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: [xsl] How to find parent's-parent's-sibling-sibling name
Date: Thu, 19 Sep 2002 08:13:02 +0200

Hello,
I am a novice to XSLT and I would like a fast fix to this.
And I hope that I am right in what I have mentioned in the Subject line of
this mail ;-)
The sample xml snippet is given below.


<BehaviourInfo ID="3">
     <Name>&text_88;</Name>
     <Trap>
       <Name>AlarmEvent</Name>
     </Trap>
     <BehaviourBitmaps>
       <BehaviourBitmapsInfo>
         <Name>&text_90;</Name>
       </BehaviourBitmapsInfo>
       <BehaviourBitmapsInfo>
         <Name>&text_91;</Name>
       </BehaviourBitmapsInfo>
     </BehaviourBitmaps>
</BehaviourInfo>

Right now I am iterating in the "BehaviourBitmapsInfo" tag. How do I find
"Trap/Name" from this position without leaving the iteration?

rgds,
Gnanendra.
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