Hi List,
I am trying to write an xsl which takes in an xsl template file as input,
parses that file, and outputs an initial call-template node for use in
building an xsl page for the application.
So the template would be something like:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template name="link">
<xsl:param name="linkid"/>
<xsl:param name="linkname"/>
<xsl:param name="pagename"/>
<xsl:param name="class"/>
</xsl:template>
</xsl:stylesheet>
And I would like the output to be something like:
<xsl:call-template name="link">
<xsl:with-param name="linkid"></xsl:with-param>
<xsl:with-param name="linkname"></xsl:with-param>
<xsl:with-param name="pagename"></xsl:with-param>
<xsl:with-param name="class"></xsl:with-param>
</xsl:call-template>
Ok, heres the problem I am having:
The xsl I am writing needs to reference the xsl namespace in order to
properly access the xsl nodes within the template using XPath. But if I do
not declare the xmlns:xsl="http://www.w3.org/1999/XSL/Transform";, the XPath
does not work. If I do declare the
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; then outputting the
xsl:templates doesn't work because the processor tries to execute the xsl
rather than just outputting it.
I cannot output an arbitratry namespace for the xsl template which is
generated and use namespace alias for mainly cosmetic reasons, but I think
management will not bend on this.
Does anyone have an idea of what might work in this situation? Is there a
way to switch the namespace prefix as well as the definition of that
namespace?
Thanks,
Alex
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