Re: [xsl] Re: Selecting a random node from source-tree

["Martin Lormes" <martin.lormes@xxxxxxx>]

----- Original Message -----
From: "Dimitre Novatchev" dnovatchev at yahoo dot com
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, September 26, 2002 5:11 PM
Subject: [xsl] Re: Selecting a random node from source-tree


> > I was thinking of an XPath expression like this:
> >
> > document('funnies.xml')/funnies/quote[random()]
> >
> > Can I avoid using extension elements?
>
> Yes, use the "randNext" template from FXSL.
>
> More information is contained in the article:
>
> "Casting the Dice with FXSL: Random Number Generation Functions in
> XSLT"
>
> http://fxsl.sourceforge.net
> /articles/Random/Casting%20the%20Dice%20with%20FXSL-htm.htm
>
> Hope this helped.


Thanks, Dimitre. Awsome article!

Unfortunately I always get the same random number (which makes perfect
sense, since I can't dynamically generate a starting number :-( )

So I must add this as a condition to my original question: the stylesheet is
static. No way of changing that.


Thanks for your help.
Martin Lormes



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