RE: [xsl] Sorting Question: Muenchian method? Substring in Key?

["Robert Koberg" <rob@xxxxxxxxxx>]

Hi,

try passing it this way:

<xsl:template match="topics">
  <div class="topics">
    <xsl:apply-templates select="topics/topic">
      <xsl:sort select="."/>
    </xsl:apply-templates>
  </div>
</xsl:template>

<xsl:template match="topic">
  <xsl:variable name="previndex" select="position()-1"/>
  <xsl:if test="not(substring(.,1,1) =
substring(/topics/topic[$previndex],1,1))">
    <div class="topicTitle"><xsl:value-of select="substring(.,1,1)"/></div>
  </xsl:if>
  <div class="topic"><xsl:value-of select="."/></div>
</xsl:template>

best,
-Rob



> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Thomas_M
> Sent: Friday, September 27, 2002 8:27 AM
> To: 'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'
> Subject: [xsl] Sorting Question: Muenchian method? Substring in Key?
>
>
> Hello. This is my first XSLT project. I'm having trouble with grouping
> sorted items (seems to be a common theme). I have a XML file like this
> (simplified):
>
> <topics>
>   <topic>Anteater</topic>
>   <topic>Aardvark</topic>
>   <topic>Beetle, Smaller European Elm Bark</topic>
>   <topic>Beetle, American Burying</topic>
>   <topic>Chimpanzee</topic>
> </topics>
>
> I would like the output to be sorted and grouped, with each group getting a
> heading:
>
> A
> Aardvark
> Anteater
>
> B
> Beetle, American Burying
> Beetle, Smaller European Elm Bark
>
> C
> Chimpanzee
>
> The corresponding part of my XSL is below.
>
>   <xsl:template match="topics">
>    <table border="1">
>       <xsl:for-each select="topic">
>         <xsl:sort select="."/>
>         <xsl:variable name="previndex" select="position()-1"/>
>         <xsl:if test="not(substring(.,1,1)
>                       = substring(/topics/topic[$previndex],1,1))">
> 		<tr><th><xsl:value-of select="substring(.,1,1)"/></th></tr>
>
>         </xsl:if>
>             <tr>
>               <td><xsl:value-of select="."/></td>
>             </tr>
>       </xsl:for-each>
>     </table>
>   </xsl:template>
>
> As you can see, I'm comparing an element in a sorted node-set with a
> document-order node-set. This works only if the XML is pre-sorted. Is there
> a way to create the sorted node-set first, so that I can both traverse and
> use it in my test?
>
> I have seen a few examples of the Muenchian method, and it would seem this
> is another (perhaps better) way solve my problem. However, I've tried
> several times to implement it and can't seem to get it right (can you use a
> substring in a key?)
>
> Thanks for any insight,
>
> - Mark.
>
> --
> Mark Thomas                       |_|
> Internet Systems Architect        -+-
> User Technology Associates, Inc.   |
> Thomas_M@xxxxxxx                  /-\
>
>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list