Subject: [xsl] sorted table elements From: Saverio Perugini <sperugin@xxxxxxxxxxxxxxxx> Date: Thu, 3 Oct 2002 10:10:29 -0400 (EDT) |
Hello, I'd like to produce a 4 column HTML table where each <td> element is alphabetically sorted from cell 1,1 to cell n,4 (where n is the required number of rows). The following is an attempt: <table> <xsl:for-each select="*[position() mod 4 = 1]"> <xsl:sort data-type="text" select="name()"/> <tr> <xsl:for-each select=".|following-sibling::node()[position() < 4]"> <td>...</td> </xsl:for-each> </tr> </xsl:for-each> </table> This code only sorts all the *[position() mod 4 = 1] elements. Therefore, only column one is sorted, whereas I wanted the entire table (an linear list from cell 1,1 to cell n,4 sorted). Can this be done? Thank You and Best Regards, S. Perugini XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Processing of large XML files, Edward L. Knoll | Thread | Re: [xsl] sorted table elements, Joerg Heinicke |
[xsl] Processing of large XML files, Edward L. Knoll | Date | [xsl] Resource recommendations for , Carrie Kaufman |
Month |