Re: [xsl] variable handling

Subject: Re: [xsl] variable handling
From: "Anita Sood" <anita_sood_77@xxxxxxxxxxx>
Date: Thu, 03 Oct 2002 17:17:28 +0000
Thanks for the lead J. I guess I need to check your code. Unfortunately some syntax errors it seems.
Thank you once again


Regards
Anita


From: "J.Pietschmann" <j3322ptm@xxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] variable handling
Date: Tue, 01 Oct 2002 21:48:03 +0200

Anita Sood wrote:
I dont know what should be the appropriate title for this problem of mine.
You appear to have a "grouping problem": You want to group
your members by team.
The usual solution is called Muenchean Grouping, described
in detail in the XSLT FAQ reachable from
 http://www.mulberrytech.com/xsl/xsl-list/
and Jeni Tennisons site:
 http://www.jenitennison.com/xslt/grouping/index.html

For your specific problem, define a key which identifies
the groups, in your case, the elements to match are the
rows, the group a row belongs to is identified by its
team child element:

<xsl:key name="row-by-team" match="row" use="team"/>

In some template, you select rows, but make sure to select
only the first row of each group by a special trick. This
way you actually got the groups, defined by it's first member,
and you only need to process the whole group, selected by the
key:
 <xsl:template match="TeamInfo">
  <teams>
    <xsl:for-each select="row[generate-id()
      =generate-id(key('row-by-team',team)[1])]">
      <team number="{team} name="{teamName}">
        <xsl:for-each select="key('row-by-team',team)">
           <member><xsl:value-of select="."/></member>
        </xsl:for-each>
      </team>
    </xsl:for-each>
  </teams>
 </xsl:template>
(untested)

HTH
J.Pietschmann



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