Subject: RE: [xsl] Select a node by name From: "Dion Houston" <dionh@xxxxxxxxxxxxxxxxxxxxx> Date: Fri, 4 Oct 2002 15:42:16 -0700 |
Hi Andreas: There's actually a couple issues here... The select issue is actually pretty easy and straight forward. To select the person element who has a name attribute of Betty, simply use the XPath: /persons/person[@name="Betty"] The second issue is that xsl:value-of outputs the text content of the node you specify. So in the case of: <xsl:value-of select="/persons/person[@name='Betty']"/> This will actually display nothing. Why? In your sample XML below, the person _element_ has no text content. If what you're looking for is (for example) the job, then use the following: <xsl:value-of select="/persons/person[@name='Betty']/@job"/> HTH! Dion -----Original Message----- From: Andreas Schlegel [mailto:schlegel@xxxxxxxxxxxxxxxxxxx] Sent: Friday, October 04, 2002 3:26 PM To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Select a node by name Hi, writing a XSL file I have the problem to get a specific node of the list. Having a XML file like this: <persons> <person name="Bill" job="Developer"/> <person name="Steve" job="Admin"/> <person name="Betty" job="CEO"/> </persons> A statement like <xsl:value-of select="person"/> won't help because I have a lot of nodes of the type PERSON. If I have a node already selected I may use <xsl:value-of select="@name"/> It's no problem to do it by for each ( <xsl:for-each select="person"> ). But I look for a way to pick a person out of the list, i.e. "Betty". Any ideas? Greetings, Andreas XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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