RE: [xsl] calculate unique items in xsl

["Michael Kay" <michael.h.kay@xxxxxxxxxxxx>]

> 
> Thanks for your help in my previous post!  Given the below 
> xml,how can I get 
> the
> the number of unique warehouse codes?  Do I need to use <xsl:key>?

Removing duplicates is the same problem as grouping, so look up
"grouping" in your favourite textbook or FAQ site.

With XSLT 1.0 there are basically two techniques. 

Simple problems on small documents (like your example) can be solved
using

  count(item[not(whcode = preceding-sibling::item/whcode)])

More complex problems, or problems on larger documents, require
Muenchian grouping using xsl:key, as described at
http://www.jenitennison.com/xslt/grouping

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> 
> <inventory>
> <item>
> <warehousecode>BA</warehousecode>
> <item>bolt</item>
> <quantity>34</quantity>
> </item>
> <item>
> <warehousecode>BA</warehousecode>
> <item>nail</item>
> <quantity>50</quantity>
> </item>
> <item>
> <warehousecode>AC</warehousecode>
> <item>tack</item>
> <quantity>5</quantity>
> </item>
> <item>
> <warehousecode>BA</warehousecode>
> <item>hammer</item>
> <quantity>10</quantity>
> </item>
> <item>
> <warehousecode>AD</warehousecode>
> <item>screwdriver</item>
> <quantity>60</quantity>
> </item>
> <item>
> <warehousecode>AB</warehousecode>
> <item>wrench</item>
> <quantity>13</quantity>
> </item>
> </inventory>
> 
> 
> Desired output:
> 
> Number of unique warehouse codes:  4
> 
> Thanks for helping an xsl newbie!!
> 
> RJ
> 
> 
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