Subject: RE: [xsl] Transforming XML to CSV From: "KIENLE, STEVEN C [IT/0200]" <steven.c.kienle@xxxxxxxxxxxxx> Date: Tue, 15 Oct 2002 08:05:33 -0500 |
The following transform will do what you want: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text"/> <xsl:template match="/"> <xsl:apply-templates select="root" /> </xsl:template> <xsl:template match="root"> <xsl:apply-templates select="row" /> </xsl:template> <xsl:template match="row"> <xsl:apply-templates select="column" /> <xsl:text>
</xsl:text> </xsl:template> <xsl:template match="column"> <xsl:text>"</xsl:text> <xsl:value-of select="."/> <xsl:text>"</xsl:text> <xsl:if test="position() != last()"> <xsl:text>,</xsl:text> </xsl:if> </xsl:template> </xsl:stylesheet> This assumes the document root in <root>. The main thing here is the use of the text output method, along with the 
 (New line) character. The xsl:if is used to determine if a comma is needed after a column. I hope this helps, Steve -----Original Message----- From: Ryan.Asleson@xxxxxxxxxx [mailto:Ryan.Asleson@xxxxxxxxxx] Sent: Tuesday, October 15, 2002 8:31 AM To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Transforming XML to CSV Hello, I wish to transform XML which looks like this: <row> <column>Value 1</column> <column>Value 2</column> <column>Value 3</column> </row> <row> <column>Value 4</column> <column>Value 5</column> <column>Value 6</column> </row> Into a comma separated values (CSV) format looking like this: "Value 1","Value 2", "Value 3" "Value 4","Value 5", "Value 6" so it can be read in a spreadsheet program. What XSL will do this? I'm having trouble because the result is not a hierarchical result. Thanks!! XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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