Subject: Re: [xsl] Fwd: Built-in *@ vs. node() From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Wed, 16 Oct 2002 17:24:40 +0200 |
Hi all,
my very small Stylsheet:
<?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet version="1.0"xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" encoding="iso-8859-1" indent="yes"/>
<xsl:template match="node()"> <xsl:copy> <xsl:apply-templates select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template>
</xsl:stylesheet>
It doesnt copy attribute nodes and i dont know why it doesnt. It matches the default attribute template which i thought would be overriden by <xsl:template match="node()">
In my XML Book "In a nutshell" it says: "node() matches all nodes regardless of type: attribute, namespace..."
and later in the same book about xsl:template it says:
"templates witch match patterns that just have a node test (*,@*, node()...) have priority -0.5" like built-in templates, but "they
[built-in templates] are also imported before all other templates,
and thus never override any explicit template rule, regardless of
priority"
so all attributes are selected by <xsl:apply-templates select="@*"/> and because they match node() and <xsl:template match="node()"> has same priority as built-in <xsl:template match="text()|@*"> BUT it has higher import precedence.
So it should match and xsl:copy with attribute should create an attribute with same name and value as the source document (Kay, XSLT 2nd edition p. 193)
But it doesnt work with xsltproc neither with saxon
Can anyone push me in the right direction to solve my problem (or how to read my books :-)
regards, janning
System Development VIRBUS AG Fon +49(0)341-979-7419 Fax +49(0)341-979-7409 joerg.heinicke@xxxxxxxxx www.virbus.de
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