[xsl] Making sure table rows are filled?

["Vic Gar" <vlg8693@xxxxxxxxxxx>]

Hello all,
With flat-ish xml (below), I need to
1) select the elements from a predetermined position (e.g, elems d1-d9)
    <xsl:variable name="table_nodes" select="/a/b/c/*[position() &lt; 
10]"/>
2) take those that have text node children
    ...and normalize-space{.}
3) make a table with rows of two name/value pairs (e.g., 
<tr><td>#9</td><td>foo</td><td>#10</td><td>bar</td></tr> )
    for-each select="$table_nodes[position() mod 2 = 1]
         <tr>
              <xsl:apply-templates select=". | ...
4) if there are an odd number of elements, only the last row of the table 
can be missing a <td> - all the preceding rows should have the requisite 2 
name/value pairs.


I tried:
<xsl:apply-templates select=". | $table_nodes[position() &gt; $here and 
position() &lt; $here+2]" mode="td"/>
The nodes that made it into $table_nodes, in doc order, are
d1 & d4-9.
but for some reason it created:
d1   (d1 value}  d4   (d4 value}
d5   (d5 value}
d6   (d6 value}  d7   (d7 value)
d7   (d7 value}  d9   (d9 value}

My understanding of what's going on here is a long way from where it should 
be.  I get why d7 was selected twice, but as for the rest (why no d8, why 
single <td> at d5, how to do this properly) can anyone explain it to me?

xml:
<a>
  <b>
     <c>
        <d1>one</d1>
        <d2></d2>
        <d3></d3>
        <d4>four</d4>
        <d5>five</d5>
        <d6>six</d6>
        <d7>seven</d7>
        <d8>eight</d8>
        <d9>nine</d9>
        <d10>ten</d10>
     </c>
  </b>
</a>

Many thanks!

_________________________________________________________________
Choose an Internet access plan right for you -- try MSN! 
http://resourcecenter.msn.com/access/plans/default.asp


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list