Subject: [xsl] How determinate what is the position of all ancestors? From: "Giovani Librelotto" <grl@xxxxxxxxxxxx> Date: Mon, 21 Oct 2002 16:59:41 +0100 |
Hello all, How I can to know the position of all ancestors? I have this XML file: <?xml version="1.0" encoding="UTF-8"?> <names> <name>Giovani</name> <family> <name>Father</name> <name>Mother</name> </family> </names> And this piece of stylesheet: <xsl:element name="position"> <xsl:for-each select="ancestor::*"><xsl:value-of select="name(.)"/>[<xsl:value-of select="position()"/>]/</xsl:for-each> </xsl:element> That generate this: <?xml version="1.0" encoding="utf-8"?> <names> <name>Giovani</name> <position>names[1]/</position> <name>Father</name> <position>names[1]/family[2]/</position> <name>Mother</name> <position>names[1]/family[2]/</position> </names> But I want this(the complete path to the node): <?xml version="1.0" encoding="utf-8"?> <names> <name>Giovani</name> <position>names[1]/name[1]</position> <name>Father</name> <position>names[1]/family[1]/name[1]</position> <name>Mother</name> <position>names[1]/family[1]/name[2]</position> </names> Thanks for your help. Regards, Giovani XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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