Subject: RE: [xsl] Newbie, question about looping From: Erick Todd <erick@xxxxxxxxxxxxxxxxxxx> Date: 23 Oct 2002 11:22:03 -0600 |
That is what I am looking for thanks. On Wed, 2002-10-23 at 10:53, Passin, Tom wrote: > [Erick Todd] > > > Here is my problem. I have an xml document of items. And I > > need to display these items in a table 3 across. > > > > So every 3 I try to put in a </tr><tr> but that is invalid. > > Has anyone had to try and do this?? > > > > Xslt is mostly about selecting a set of nodes and then doing something > with them. So you should try to find solutions that select the right > set of nodes, rather than think about looping through. It is usually > more productive. > > You also have to think in terms of creating complete elements at a time, > not parts. > > In this case, you want to select every third item, because those > elements will represent the start of each row. For each item in that > set of nodes, you want to output it and its next two sibling items, > wrapped in <tr>..</tr> element. Right? > > Here is a simple way to do that, assuming that you have a series of > "item" elements like this: > > <root> > <item>1</item> > <item>2</item> > ... > </root> > > ================================================= > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output encoding='iso-8859-1'/> > > <xsl:template match="/root"> > <results> > <xsl:apply-templates select='item[position() mod 3 =0]'/> > </results> > </xsl:template> > > <xsl:template match='item'> > <tr> > <td><xsl:value-of select='.'/></td> > <td><xsl:value-of select='following-sibling::item[1]'/></td> > <td><xsl:value-of select='following-sibling::item[2]'/></td> > </tr> > </xsl:template> > > </xsl:stylesheet> > ==================================================================== > > Cheers, > > Tom P > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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