Re: [xsl] xsl:number useless with xsl:sort?

Subject: Re: [xsl] xsl:number useless with xsl:sort?
From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx>
Date: Mon, 04 Nov 2002 12:05:00 +0200
Jan Krattiger wrote:

i use xsl:sort to sort the output. now i need something like xsl:number to
give the elements numbers from 1-n, but i need the sorted one to be
numbered.
xsl:number uses the unsorted, "original" xml to number. one possiblity would
be sorting the xml before transforming... but that not possible in my case..

does anyone have a solution?

Well, temporary tree aka result tree fragment? That's obviously not a very effective, but at least simple and clear solution - first sort to the variable, then convert it to a nodeset and process using xsl:number.


--
Oleg Tkachenko
eXperanto team
Multiconn Technologies, Israel


XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list



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