Re: [xsl] xslt replace special characters

[Greg Faron <gfaron@xxxxxxxxxxxxxxxxxx>]

At 01:14 PM 11/8/2002, you wrote:
> thank you.  it works if i just use it for one character.  can i put in 
> more than one character in the pattern variable at once?  if i keep 
> calling the template, obviously i will get the string variable the number 
> of i call the template.  so what do you suggest that i do if i have a 
> string like this.
> http://www.domain.com?xxx=yyy&www=y
> > > i want to convert
> > >
> > > ? to %3f
> > > = to %3d
> > > & to %26

You must call the template multiple times, each time feeding it the result 
of the previous replacement.  The following command
    <xsl:call-template name="replace">
      <xsl:with-param name="string">
        <xsl:call-template name="replace">
          <xsl:with-param name="string">
            <xsl:call-template name="replace">
              <xsl:with-param name="string" select="$url"/>
              <xsl:with-param name="pattern" select="'&amp;'"/>
              <xsl:with-param name="replacement" select="'%26'"/>
            </xsl:call-template>
          </xsl:with-param>
          <xsl:with-param name="pattern" select="'='"/>
          <xsl:with-param name="replacement" select="'%3d'"/>
        </xsl:call-template>
      </xsl:with-param>
      <xsl:with-param name="pattern" select="'?'"/>
      <xsl:with-param name="replacement" select="'%3f'"/>
    </xsl:call-template>
transforms
http://www.domain.com?xxx=yyy&www=y
into
http://www.domain.com%3fxxx%3dyyy%26www%3dy
if the former was located in the variable $url.


Greg Faron
Integre Technical Publishing Co.



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