RE: [xsl] key(), generate-id question

["Américo Albuquerque" <aalbuquerque@xxxxxxxxxxxxxxxx>]

Hi Endre.

Ttry this.

 <xsl:template match="page">
  <xsl:copy>
  <xsl:apply-templates select="element[@_id] | element[not(@_id)]"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="element">
  <element>
  <xsl:attribute name="xmi.id">
  <xsl:choose>
   <xsl:when test="@_id">
   <xsl:value-of select="@_id"/>
   </xsl:when>
   <xsl:otherwise>
   <xsl:call-template name="generate-id"/>
   </xsl:otherwise>
  </xsl:choose>
  </xsl:attribute>
  </element>
 </xsl:template>

 <xsl:template name="generate-id">
  <xsl:variable name="last"
select="number(substring-after(preceding-sibling::element[@_id][1]/@_id,
'id'))"/>
  <xsl:variable name="this"
select="count(preceding-sibling::element[not(@_id)])+1"/>
  <xsl:variable name="temp" select="concat('00000',$last+$this)"/>
  <xsl:value-of
select="concat('id',substring($temp,string-length($temp)-5))"/>
 </xsl:template>

they work with this xml:
<page>
 <element _id="id000001"/>
 <element _id="id000002"/>
 <element _id="id000003"/>
 <element />
 <element />
</page>

And produce this:
<page>
 <element _id="id000001"/>
 <element _id="id000002"/>
 <element _id="id000003"/>
 <element _id="id000004"/>
 <element _id="id000005"/>
</page>

If the structure of your xml is diferent (probably is) then you can
change the 'element' in the templates by 'node()'
Hope that this helps you.


-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Endre
Magyari
Sent: Monday, November 11, 2002 7:30 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] key(), generate-id question


> You can't control how generate-id() works, but you could do something
> like write a named template that will generate the ID. For example,
> you could count the number of preceding elements that don't have an
> _ID attribute and then add that value to the numeric part of the
> nearest preceding element that *does* have an _ID attribute. All
> doable with normal XSLT functions.


Based on this, as far as now I could do an enumeration of all the _id
values (as numbers) from the document, but I have no idea how to select
the one with the maximal value out of them. And Also, I have no idea
how/where to store the new id values being assigned. The problem is that
I've no experience with declarative languages. I can not get used to the
idea that a variable can not vary. What I would do is that (if
curr_value > max) max = curr_value. But how to do this here? Any help is
greatly appreciated.

<!-- ID Generator-->
<xsl:template name="idgen">
    <xsl:for-each select="node()">
        <xsl:for-each select="@_id">
            <xsl:number value="substring-after(current(),'id')"/>;
        </xsl:for-each>
    </xsl:for-each>
</xsl:template>

Thank you,
Endre


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