Subject: [xsl] How to address generic unknown elements ! From: Delaney Robin <Robin.Delaney@xxxxxxx> Date: Thu, 14 Nov 2002 13:04:27 +0100 |
I have been using XML's with "known" element names that I could address but I need to change it to be more generic so that I can run a stylesheet over an XML without knowing the structure beforehand: XML: <ABC> <BCD> <EFG> <etc.....> </EFG> </BCD> <BCD> <EFG> <etc.....> </EFG> </BCD> </ABC> old XSL: <xsl:template match="ABC"> <xsl:for-each select="BCD[1]//*[not(*)]"> <xsl:value-of select="local-name()"/> </xsl:for-each> </xsl:template> <xsl:template match="BCD"> <xsl:for-each select=".//*[not(*)]"> <xsl:value-of select="node()"/> </xsl:template> That gives me the drill down node-names from the first occurence of BCD and the drill down node values of all BCD's. I'm trying to have: (or similar!) <xsl:template match="/"> <xsl:for-each select="?//*[not(*)]"> ???stuck here??? <xsl:value-of select="local-name()"/> </xsl:for-each> <xsl:for-each select=".//*[not(*)]"> <xsl:value-of select="node()"/> </xsl:template> My match is now "/" (to process all) instead of ABC as I don't have specific names to reference. How do I reference BCD[1] (I know it always begins 2 levels down from the top node) and drill down to the end of the node 1 time to get the node-names without knowing it's name ? I only want it to do the local-name() piece once (ie. for the 1st element) whilst doing node() for all elements. The node() bit is OK but I can't get the local-name() piece to deliver what I want instead I end up with "number of iterations" x node-names. I guess for-each is wrong but I think I'm stuck with 1 template match "/" or am I thinking wrongly (again!). Any help appreciated Thanks, Robin XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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