Subject: Re: [xsl] Generic XSLT Sorting Template From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Sat, 16 Nov 2002 04:08:06 +0100 |
I am trying to find a way to create a generic xsl sorting function that takes 5 parameters, which are the names of the nodes to sort.
I dont understand how to pass parameters to an xsl stylesheet, but basically i just want a simple sorting function that sorts the xml and returns a sorted version of the xml using xsl:copy.
So far this is what i got:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:template name="GenericSort"> <!-- The sort fields --> <xsl:param name="SortField0" select="" />
You should get an error here -------------^^ ("missing argument") Change it to select="''", same for the rest.
<xsl:param name="SortField1" select="" /> <xsl:param name="SortField2" select="" /> <xsl:param name="SortField3" select="" /> <xsl:param name="SortField4" select="" />
<xsl:copy >
<xsl:apply-templates> <xsl:sort select="$SortField0" />
<xsl:sort select="$SortField1" /> <xsl:sort select="$SortField2" /> <xsl:sort select="$SortField3" /> <xsl:sort select="$SortField4" /> </xsl:apply-templates> </xsl:copy> </xsl:template>
</xsl:stylesheet>
i want the first sort field (sortfield0) to sort on the global node-set (ancestor::*[next-sibling()]) ??
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