Subject: [xsl] Linefeed-treatment in fop 0.20.4 From: RShonk@xxxxxxxxxxxxx Date: Tue, 19 Nov 2002 16:12:04 -0500 |
Can anyone tell me if there is an easier way to do this? My NOTE_TEXT node is returned from an Oracle blob object which contains line-feed characters and is multi-line. When rendering the linefeed '\n' was ignored and everything ended up on one line. I tried to use linefeed-treatment and white-space-treatment = "preserve", but these are not yet implemented in fop 0.20.4 Here is the xslt workaround I came up with to get the multiline results I was looking for, but there has got to be an easier way. <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:Date="xalan://java.util.Date" xmlns:Token="xalan://java.util.StringTokenizer"> --- trimmed header / fo:table nodes --- <fo:table-cell> <xsl:apply-templates select="NOTE_TEXT"> <xsl:with-param name="noteToken" select ="Token:new(NOTE_TEXT,' ')"/> </xsl:apply-templates> </fo:table-cell> <xsl:template match="NOTE_TEXT"> <xsl:param name="noteToken"/> <xsl:call-template name="note.loop"> <xsl:with-param name="i" select="1"/> <xsl:with-param name="noteMax" select="Token:countTokens($noteToken)"/> <xsl:with-param name="noteToken" select="$noteToken"/> </xsl:call-template> </xsl:template> <xsl:template name="note.loop"> <xsl:param name="i"/> <xsl:param name="noteMax"/> <xsl:param name="noteToken"/> <xsl:if test="$i <= $noteMax"> <fo:block> <xsl:value-of select="Token:nextToken($noteToken)"/> </fo:block> <xsl:if test="$i < $noteMax"> <xsl:call-template name="note.loop"> <xsl:with-param name="i" select="$i + 1"/> <xsl:with-param name="noteMax" select="$noteMax"/> <xsl:with-param name="noteToken" select="$noteToken"/> </xsl:call-template> </xsl:if> </xsl:if> </xsl:template> Thanks in advance, Richard Shonk Flowserve Corp. Programmer / Analyst Parts Distribution Center Moosic, Pa. (570) 451-2225 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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