Re: [xsl] how to group nodes by id?

["Vasu Chakkera" <vasucv@xxxxxxxxxxx>]

Dear Artur,

Your XML is not well formed because the id attribute value is not in
quotes.
for example,
>  <elem id=1>
should have been
  <elem id="1">

That said,
try the following code.
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:output method="xml" indent="yes"/>
 <xsl:template match="elems">
  <elems>
   <xsl:for-each select="elem[not(@id = preceding-sibling::elem/@id)]">
    <xsl:variable name="elem-id" select="@id"/>
    <elem id = "{$elem-id}">
     <xsl:for-each select="/elems/elem[@id = $elem-id]">
      <xsl:copy-of select="*"/>
     </xsl:for-each>
    </elem>
   </xsl:for-each>
  </elems>
 </xsl:template>
</xsl:stylesheet>

HTH
Vasu
----- Original Message -----
From: "Artur Matysiak" <majffa@xxxxxxxxx>
To: <XSL-List@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, December 02, 2002 3:48 PM
Subject: [xsl] how to group nodes by id?


>
>  hi
>  does anybody know how to convert the following XML:
>
>  <elems>
>  <elem id=1>
>   <elem id=1/>
>  </elem>
>  <elem id=1>
>   <elem id=2/>
>  </elem>
>  <elem id=2>
>   <elem id=1/>
>  </elem>
>  <elem id=2>
>   <elem id=2/>
>  </elem>
>  </elems>
>
>  to the form
>
>  <elems>
>  <elem id=1>
>   <elem id=1/>
>   <elem id=2/>
>  </elem>
>  <elem id=2>
>   <elem id=1/>
>   <elem id=2/>
>  </elem>
>  </elems>
>
>  thanks Artur
>
>
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