Re: [xsl] ancestors property?

Subject: Re: [xsl] ancestors property?
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Tue, 03 Dec 2002 18:56:21 -0500
Michael,

"ancestor()" uses an ancient syntax long forgotten in the Annals of XSLT.

Try the axis specifier "ancestor::", as in:

<xsl:template match="inside[ancestor::*/@myprop='123']">
  ...
</xsl:template>

And update your reference materials!

Cheers,
Wendell

At 06:56 PM 12/3/2002, you wrote:
If I have something like this:

<outside myprop='123'>
  <mid>
    <inside>456</inside>
  </mid>
</outside>


How would I write my match for my <xsl:template> for the <inside> node so that that template would only match if outside's myprop was equal to '123' (and another template might match only '234' for example. I want there to be any number of nested levels between the <outside> and <inside> tags. I tried using ancestor() but I must have messed something up because it said ancestor didn't exist.


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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