Subject: RE: [xsl] a*b, sum(c*d), sorted on <sort> From: "Andrew Welch" <awelch@xxxxxxxxxxxxxxx> Date: Wed, 4 Dec 2002 16:30:18 -0000 |
I would use a use a temporay tree containing a sorted list of <item> with the first part of the calculations complete, so you would have something like: <root> <item><a*b>20</a*b><sumCD>18</sumCD></item> <item><a*b>6</a*b><sumCD>40</sumCD></item> .... Then produce your table by applying-templates to the temporary tree, using sum() on the <sumCD> element to get the cumulative column. cheers andrew > Here is my XML: > > <root> > <item><a>1</a><b>2</b><c>2</c><d>7</d><sort>3</sort></item> > <item><a>2</a><b>3</b><c>5</c><d>8</d><sort>2</sort></item> > <item><a>3</a><b>4</b><c>1</c><d>2</d><sort>4</sort></item> > <item><a>4</a><b>5</b><c>2</c><d>9</d><sort>1</sort></item> > </root> > > For each <item> I need to produce a row containing > cells for a*b and cumulative c*d where the items > are taken sorted on <sort>: > > +-----+----------+ > | a*b | sum(c*d) | > +-----+----------+ > | 20 | 18 | > +-----+----------+ > | 6 | 58 | > +-----+----------+ > | 2 | 72 | > +-----+----------+ > | 12 | 74 | > +-----+----------+ > > The above a gross simplification, but I would like to get input from > people on how they would structure the problem as it has a lot > more detail in reality. In a nutshell, I have both recursive and > non-recursive calculations to perform in each row. > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] a*b, sum(c*d), sorted on <sor, Dan Diebolt | Thread | RE: [xsl] a*b, sum(c*d), sorted on , McNally, David |
RE: [xsl] Problem using translate t, Yates, Danny (ANTS) | Date | RE: [xsl] Newbie encoding query, Passin, Tom |
Month |