RE: [xsl] Test for current node being an element or attribute?

Subject: RE: [xsl] Test for current node being an element or attribute?
From: Américo Albuquerque <aalbuquerque@xxxxxxxxxxxxxxxx>
Date: Tue, 10 Dec 2002 19:07:49 -0000
Maby generate-id()=generate-id(../namespace::*) ??


-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Dimitre
Novatchev
Sent: terça-feira, 10 de Dezembro de 2002 18:40
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Test for current node being an element or attribute?



"Michael Kay" <michael.h.kay@xxxxxxxxxxxx> wrote in message
news:000601c2a060$f5b8d1b0$6401a8c0@xxxxxxxxxx
> > 
> > what about:
> > 
> > <xsl:if test="../@*[current()]">
> > 
> 
> Stop guessing, and read the spec.
> 
> current() returns a node-set. When used in a predicate, [current()] 
> returns true if the node-set is non-empty. It is.


OK, here's one correct test if the current node is an attribute:

count(. | ../@*) = count(../@*) 


Can you, friends, guess how to test if the cirrent node is a namespace?
:o)




=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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