Re: [xsl] Marking every second row

[Sorin Marti <mas@xxxxxxxxxx>]

Thanks to everyone who helped me! Now it works!!



Greets

Sorin

Jeni Tennison wrote:

> Hi Sorin,
>
> > I got an very simple XSL-File wich produces following output from a very
> > simple XML-File
> >
> > <table>
> > <tr><td>aaa</td></tr>
> > <tr><td>bbb</td></tr>      <-- X
> > <tr><td>ccc</td></tr>
> > <tr><td>ddd</td></tr>      <-- X
> > <tr><td>eee</td></tr>
> > <tr><td>fff</td> </tr>      <-- X
> > </table>
> >
> > Now I want the background of the lines which are marked with an X in 
> > another color.
> >
> > So how do I select every second row of my output?
>
> Using this output as the input for a transformation, you can do
> something like:
>
> <xsl:template match="table">
>  <table>
>    <xsl:for-each select="tr">
>      <tr>
>        <xsl:if test="position() mod 2 = 0">
>          <xsl:attribute name="bgcolor">blue</xsl:attribute>
>        </xsl:if>
>        <xsl:copy-of select="*" />
>      </tr>
>    </xsl:for-each>
>  </table>
> </xsl:template>
>
> This loops over the tr elements, creates a copy and adds a bgcolor
> attribute if the position of the tr element is even (which is tested
> with position() mod 2 = 0).
>
> You could probably do something similar when you're actually creating
> this table in your stylesheet, but without seeing the input to that
> transformation I can't be certain.
>  
> Cheers,
>
> Jeni
>
> ---
> Jeni Tennison
> http://www.jenitennison.com/
>
>
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



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