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Subject: RE: [xsl] Autonumbering with XSLT From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Mon, 6 Jan 2003 15:31:02 -0000 |
>
> <xsl:for-each select="//TABLE">
> <xs:value-of select="position()"/>
> </xsl:for-each>
>
> For this I get back (1,2,3,4,5) as all the <TABLE> elements
> belong to the node-list created by "//TABLE" and position()
> returns the location in the node-list not in the parent node.
> What I really want back is (1,2,1,2,3).
>
> Any suggestions?
>
<xsl:for-each select="DB">
<xsl:for-each select="TABLE">
<xs:value-of select="position()"/>
</xsl:for-each>
</xsl:for-each>
Alternatively, use xsl:number, or count(preceding-sibling::*).
Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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