Subject: Re: [xsl] using xsl to substitute synonyms or translate From: "Thomas McDonald" <tomandlis@xxxxxxxxxxx> Date: Tue, 07 Jan 2003 16:23:38 -0500 |
where 'nameId' would be a new attribute, e.g., <nflName nameId='49ers'> <alias>San Francisco</alias> </nflName>
<xsl:template match="names"> <xsl:for-each select="$nameLookupDoc"> <xsl:value-of select="key('nameNumKey',.)/alias"/> </xsl:for-each> </xsl:template>
From: "Thomas McDonald" <tomandlis@xxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] using xsl to substitute synonyms or translate Date: Tue, 07 Jan 2003 15:36:22 -0500
I have a problem that I think is similar to translating words in one language to words in another language and I was wondering if I could use xsl to do it.
I know what my source input will be (example below) and I know what I want to output to be, but I can't fathom how to build an xsl to get the output. I thought I could use the translate function, but there would be a long list of things to translate. There are 32 teams and I want to use this process again (on something unrelated) for a list of over 300 items.
Here is what my source document will look like
<nflTeamNames> <name>49ers</name> <name>Cowboys</name> . . . <name>Seahawks</name> <nflTeamNames>
Here is what I want the output to look like:
<nflCities> <city>San Francisco</city> <city>Dallas</city> . . . <city>Seattle</city> </nflCities>
In case you don't know American football the 49ers are the San Francisco team, the Cowboys are the Dallas team and so on. :-)
Regards,
Tom
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