Subject: Re: [xsl] How do I access the nodeset that the IDREF refers to? From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Date: Wed, 08 Jan 2003 18:12:26 -0500 |
<xsl:variable name="linkRef"> <xsl:value-of select="id(subnode/link[@idr])" /> </xsl:variable>
I hope that helps, Wendell
Hi all,
I'm not sure if I simply didn't use the right words, or I couldn't find the right combination of words, but I have not quite found the answer to my question in the FAQ or the archives.
Given a DTD similar to this:
<!ELEMENT root (subnode)*> <!ELEMENT subnode (link)*> <!ELEMENT link EMPTY>
<!ATTLIST subnode id ID #REQUIRED>
<!ATTLIST link idr IDREF #REQUIRED>
What I would like to know is how I can access the nodeset of the subnode element listed within the link element. An example xml file might be:
<root> <subnode id="a" /> <subnode id="b"> <link idr="c" /> <link idr="d" /> </subnode> <subnode id="c"> <link idr="e"> </subnode> <subnode id="d" /> <subnode id="e" /> </root>
An application might be to sort the list of four subnodes (a,b,c,d) based on their links. An algorithm might be:
1. for every not(subnode/link), display subnode id
2. for every (subnode/link)
2a. choose
when link reference node contains link
repeat step 2 with link reference node
otherwise
if link reference has not been displayed
display link reference id
2b. display subnode id
My question is essentially: how would I create a variable that contains the nodeset of the link reference? First I would need it to test the link to determine if the link itself had links. Next I would want to pass that link back into step two so that I could query its links.
Would the following XSL be something close?
<xsl:variable name="linkRef"> <xsl:value-of select="id(subnode/link[@idr])" /> </xsl:variable>
Thanks in advance! Bix
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