Re: [xsl] How I could produce xml without xmlns:* ???

[Michael Pediaditakis <mp49@xxxxxxxxx>]

You could add a post-processing step with something such as:

<xsl:template match="*">
  <xsl:element name="{local-name()}">
     <xsl:for-each select="attribute::*">
       <xsl:attribute name="{local-name(.)}">
          <xsl:value-of select="."/>
       </xsl:attribute>

     </xsl:for-each>
     <xsl:apply-templates select="*|text()"/>
  </xsl:element>
</xsl:template>

I'm not sure if it works, but I think it used to work when I created
it!

Cheers,

Mike.


Andrey Solonchuk wrote:
> Hello xsl-list,
>
>   How I could produce xml without xmlns:*
>
>   I use the xsl
>   
> <?xml version='1.0'?>
> <xsl:stylesheet
>   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0"
>   xmlns:xalan="http://xml.apache.org/xalan";
>   xmlns:my="http://my";
>   xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias";
>   exclude-result-prefixes="xalan my xsl xmlns axsl">
> <xsl:namespace-alias stylesheet-prefix="axsl" result-prefix="xsl"/>
>
> <xsl:output method="xml" indent="yes" xalan:indent-amount="5"/>
>
> <xsl:key name="test" match="field" use="."/>
> <my:import>
>  <field id="1">11</field>
>  <field id="2">11</field>
>  <field id="3">12</field>
> </my:import>
>
> <xsl:template match="/">
>  
>  <xsl:copy-of select="document('')//my:import/"/>
>
> </xsl:template>
>
> </xsl:stylesheet>
>
> and in output I get the next
>
> <?xml version="1.0" encoding="UTF-8"?>
> <my:import xmlns:my="http://my";                              !!!!!!
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";             !!!!!!
> xmlns:xalan="http://xml.apache.org/xalan";                    !!!!!!
> xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias";>      !!!!!!
>  <field id="1">11</field>
>  <field id="2">11</field>
>  <field id="3">12</field>
> </my:import>



XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list