Subject: RE: [xsl] generating <a href="#section"> menus. Related to <xsl:for-each> and generate-id() From: "Sherzod Ruzmetov" <xslt@xxxxxxxxxxxx> Date: Tue, 14 Jan 2003 08:44:14 -0500 |
:Change : : <xsl:attribute name="href"> : #sect_ : <xsl:number value="position()" format="I"/> : </xsl:attribute> : <xsl:value-of select="title"/> : :to : : <xsl:attribute name="href"> : <xsl:text/>#<xsl:value-of select="generate-id()" /> : </xsl:attribute> : <xsl:value-of select="title"/> See, I tried that, but <sect> nodes should be bookmarked with respective ids too, right? Otherwise when you click on the link the browser wouldn't scroll down to that section. I dont' see anything wrong with the current implementation, but at the learning stage I tend to be a little too curious, I am afraid <grin />. To go further with my nonsense... I tried: <xsl:template match="sect"> <a name="{generate-id()}"><xsl:value-of select="title" /></a> </xsl:template> to book mark each section with unique name. And somewhere else, I wanted to get the list of all the generated names(ids) and titles for the table of contents. But didn't take me too long to realise this trick was a little above me. Please, tell me its not possible. I won't be disappointed! sherzod XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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