Re: [xsl] how to "save" a context?

[S Woodside <sbwoodside@xxxxxxxxx>]

Gah! It's huge!

Seriously it looks like this will generate a string that, when assigned 
to a variable, and selected upon, will act as the correct XPath. Is 
that right?

It has:  <xsl:value-of select="msxsl:node-set($theResult)"/>

Does it require MSxml? Can I turn $theResult (which is a string, 
right?) into an XPath expression I can use in a select statement, 
without needing MSXML?

simon

On Tuesday, January 14, 2003, at 02:23  PM, Dimitre Novatchev wrote:

> Build the XPath expression for that node.
>
> One example way of doing this (for any type of node) this is presented
> at:
>
> http://www.topxml.com/code/default.asp?p=3&id=v20010323001030
>
>
> =====
> Cheers,
>
> Dimitre Novatchev.
> http://fxsl.sourceforge.net/ -- the home of FXSL
>
>
> "S Woodside" <sbwoodside@xxxxxxxxx> wrote in message
> news:C773ADAA-27F2-11D7-AD3E-000393414368@xxxxxxxxxxxx
> > I want to "save" a context, e.g., when I'm in a specific context
> node,
> > I want to be able to serialize the context node such that I can pass
> > that serialization as a string or what not, to another XSLT that
> > processes the same original XML. Then I could simply
> > select="deserialize(myserializedString)" and jump to the same node.
> > Assuming the XML hasn't changed.
> >
> > I read the spec and the FAQ... doesn't seem to be an easy way to do
> > this.
> >
> > FWIW, the string has to go through an HTML forms client/server
> > roundtrip, it will be stored as a parameter in an HTML form, then
> when
> > they submit, the string will be used to access a subtree of the
> > original XML to expand that subtree and make new HTML forms for the
> > subtree.
> >
> > simon
> >
> > ---
> > www.simonwoodside.com
> >
> >
> >  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
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