Re: [xsl] Incrementing a variable in XSL

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

The question was:

> I want to increment a variable in <xsl:for-each ..,

that is, to obtain a value, reflecting the relative position of the
current node in the node-list.

This is returned always by:

position()

while using structural dependencies (e.g. preceding-sibling) may have
nothing to do with the nodelist.


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL



"Ross Ken" <Ken.Ross@xxxxxxxxxxxxxx> wrote in message
news:FE3F057E54E9774EB5129BACAF59FC760758F1@xxxxxxxxxxxxxxxxxxxxxxxxx
> In short you can't.
> 
> You can simulate it by using <xsl:value-of
select="count(preceding::a)+1"/>.
> 
> HTH,
> 
> Ken Ross
> Ph: +61 7 32359370
> Mob: +61 (0)419 772299
> Email: Ken.Ross@xxxxxxxxxxxxxx
> 
> 
> -----Original Message-----
> From: Mukul [mailto:mukulw3@xxxxxxxxx]
> Sent: Thursday, 16 January 2003 3:37 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Incrementing a variable in XSL
> 
> 
> Hello ,
> I have a simple XML file as below:
> <?xml version="1.0" encoding="UTF-8"?>
> <docroot>
>   <a>1</a>
>   <a>2</a>
>   <a>3</a>
>   <a>4</a>
> </docroot>
> 
> I have written a XSL stylesheet as below:
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> 
> <xsl:template match="docroot">
>     <xsl:variable name="var">1</xsl:variable>
>     <xsl:for-each select="a">
>        <xsl:value-of select="$var"/>  
>        <!-- incrementing $var ?? --> 
>     </xsl:for-each>    
> </xsl:template>
> </xsl:stylesheet>
> 
> I want to increment a variable in <xsl:for-each ..,
> and print it with <xsl:value-of ..
> 
> There is a situation where in the XML file, a tag
> repeats and I want to output the no's 1, 2, 3 etc in
> the output with each tag instance.
> 
> How can I do this?
> 
> Regards,
> Mukul
> 
> 
> 
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