Re: [xsl] dynamic construction of path based on param

[Oleg Tkachenko <olegt@xxxxxxxxxxxxx>]

raven wrote:
> I want to dynamically construct a path based on a
> param called $course. Here is my current code:
>
> <xsl:if test='contains($course, "510")'>
> 	<xsl:variable name="path" select="x510" />
> </xsl:if>
>
> <xsl:if test='contains($course, "340")'>
> 	<xsl:variable name="path" select="x340" />
> </xsl:if>
>
>
> <xsl:apply-templates select='syllabus/$path'/>
A number of mistakes: local variable's scope is its parent element, so both of 
your variables go out of the scope immediately. Second - variables are not 
macros, <xsl:variable name="path" select="x510" /> means the variable is bound 
to *result* of evaluation of 'x510' xpath expression. And syllabus/$path is 
syntax error in XPath.
What you can do (but it looks a litle bit strange) is

<xsl:variable name="path">
	<xsl:if test='contains($course, "510")'>
		<xsl:value-of select="x510" />
	</xsl:if>

	<xsl:if test='contains($course, "340")'>
		<xsl:value-of select="x340" />
	</xsl:if>
</xsl:variable>

<xsl:apply-templates select='syllabus/*[local-name() = $path]'/>

But that looks like a very convolute (and namespace-buggy) version of

	<xsl:if test='contains($course, "510")'>
		<xsl:apply-templates select='syllabus/x510'/>
	</xsl:if>
	<xsl:if test='contains($course, "340")'>
		<xsl:apply-templates select='syllabus/x340'/>
	</xsl:if>

--
Oleg Tkachenko
eXperanto team
Multiconn Technologies, Israel


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