Re: [xsl] How to join elements

[Oleg Tkachenko <olegt@xxxxxxxxxxxxx>]

Ian Stokes-Rees wrote:
> I have spent 30 minutes scanning the XSLT FAQ (on top of looking through the
> XSLT spec, and random docs and materials) and could not come up with any
> solution to this problem:
>
> <xsl:for-each select="//node"><xsl:value-of select="@name"/>,</xsl:for-each>
>
> outputs:
>
> a,b,c,d,
>
>        ^----------PROBLEM
>
> The problem is I do not want the last "comma" since in my output format this
> is illegal.  I do not know how many node/@name attributes will appear, so
> concat is not a solution.  FWIW, node elements can be nested inside node
> elements, and this is producing a comma separated list of all node names in
> the instance document.

Just don't add comma after last node:

<xsl:for-each select="//node">
	<xsl:value-of select="@name"/>
	<xsl:if test="position()!=last()">,</xsl:if>
</xsl:for-each>

--
Oleg Tkachenko
eXperanto team
Multiconn Technologies, Israel


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