Re: [xsl] Transforming XML to HTML Table

[Oleg Tkachenko <olegt@xxxxxxxxxxxxx>]

Nick Foster wrote:

> but I only got the value of the first sample in all columns.  Is there a
> way of looping through the $columntitles/labels and selecting the sample
> where the label matches  in the current row?

Try
<xsl:for-each select="$columntitles">
	<TD>							
		<xsl:value-of select="$samples[label=current()/label]/displayval"/>
	</TD>
</xsl:for-each>

But what's order? You've got "sample 1" in first row and "Sample 1" in the 
second one. Is this a typo?

--
Oleg Tkachenko
eXperanto team
Multiconn Technologies, Israel


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