Subject: Re: [xsl] constructing the Node Sets From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 30 Jan 2003 09:51:42 GMT |
> It still seems passing strange to me that "preceding::c[1]" should give > different results than "(preceding::c)[1], ordering (and so [1]) are only defined in a step. but an Xpath expression, including () expressions only return sets. You may thave wanted (preceding::c) to return something in reverse doc order, but what about (preceding::c|following::c|id('ggg')|$x) here intuition is less helpful about any natural order so the spec just specifies that the if you filter such an expresion with a [] predicate then the current node list is produced by sorting forwards document order. (Actually it cunningly hides this fact by instead stating that the default axis is child:: but the _only_ effect of this default axis is to specifying the ordering) This is all different (and less natural) in Xpath2 which is based on sets rather than lists. Set union naturally does "the right thing" but the natural operation on lists is concatenation which isn't usually what's wanted, so to get the right behaviour Xpath2 drafts specify that certain operations (ike / and |) explictly sort and remove duplicates to obtain a list in doc order. This works but is less natural to specify as you have to specify this behaviour on each operation. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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