Re: [xsl] JD and Java Extension

["Spencer Bruce" <spencer@xxxxxxxxxxxx>]

> Just by reading the syntax class name/function. Try following statement:
>
> <xsl:value-of select="ExtensionTest:test()"
>
> Cheers,
>
> Juergen
>

Sorry, but that did not work either - it produces a new error:

jd.xml.xslt.parser.XsltParseException: cannot parse path expression
(baseUri='stylesheet' Attribute=select , Element=xsl:value-of (line 6)
nested exception = 'jd.xml.xpath.parser.XPathParseException: no namespace
uri defined for prefix 'ExtensionTest' in "ExtensionTest:test(.)"
(offset=21)')

Also, we would prefer it if, just like with Xalan and Saxon, you can declare
the class once and then just refer to it from its namespace.

Do you have any other suggestions?

Thanks

Spencer Bruce


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