RE: [xsl] 2 XML source

["Kienle, Steven C [IT/0200]" <steven.c.kienle@xxxxxxxxxxxxx>]

If you know the maximum number of files you need to join together, you could
pass their names in through that number of parameters.  E.G.

<xsl:param name="file-1" select="''"/>
<xsl:param name="file-2" select="''"/>

....

	<xsl:if test="string-length($file-1) != 0" />
          <xsl:value-of select="document($file-1)/XPath"/>
      </xsl:if>

...

If you really have an unknown number of files to work on, then the approach
Jürgen suggests is probably the simplest and quickest. 

	Steve

-----Original Message-----
From: David Alcantara [mailto:wwwdavid@xxxxxx]
Sent: Wednesday, March 12, 2003 8:35 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: AW: [xsl] 2 XML source


Thank you,

but it´s  not so simple. :-(

every day i get approx. 100 XML files like 030312_01.xml (XML name =
date+position) and i want to have only one XSL :-)
Because every day other application creates 100's of xml files from which i
need to filter some data out of these files. As you said in your mail that
to incorporate the xml file names into the XSL File, i think in my case it
is difficult to type all the file names into the XSL File. So in this case I
request some other solution which suite my need given above.
maybe is easily make a C program who integreate the 100 xml files in other
one.
Is there a way to make C or C++ program.

Regards
david

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