Subject: RE: [xsl] Getting the value of the tag itself. From: Américo Albuquerque <aalbuquerque@xxxxxxxxxxxxxxxx> Date: Thu, 20 Mar 2003 15:34:23 -0000 |
Hi. > -----Mensagem original----- > De: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] Em nome de Simon Kelly > Enviada: quinta-feira, 20 de Março de 2003 15:08 > Para: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Assunto: [xsl] Getting the value of the tag itself. > > > Hi all, > > I know haow to get all the relevent information from a node, > but I am struggling to remeber how to get the nodes name > itself. IE if I have a node called <table name="table1"> how > do I print out it's name table, and not the @name table1?? You could use <xsl:value-of select="name()"/> Or <xsl:value-of select="local-name()"/> The first will give you the "complete" name, i.e., with any prefix it might use, the second will give you the name unprefixed Example <doc xmlns:x="..."> name()='doc' local-name()='doc' <x:para> name()='x:para' local-name()='para' <para_child/> name()='para_child' local-name()='para-child' <x:para_child/> name()='para_child' local-name()='para-child' </x:para> <para/> name()='para' local-name()='para' </doc> Hope that this helps you XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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