Subject: [xsl] Copy XML into an attribute From: "Fran" <franciscojose@xxxxxxxxxxx> Date: Tue, 25 Mar 2003 13:57:48 +0100 |
Hi list!! I have the following xml : <parents> <parent> <children> <child number="0" state="0"> <property idproperty="111"/> <property idproperty="112"/> <property idproperty="113"/> </child> <child number="0" state="0"> <property idproperty="111"/> <property idproperty="112"/> <property idproperty="113"/> </child> </children> </parent> <parent> .... </parent> ..... I have the following xslt code to loup through parents and I have an image for each parent, I want also to copy in a attribute all the xml code exactly as I have.(<children><child ....</child></children>), with exactly all nodes and attributes. I'm doing this but my code don't work. ..... <xsl:template match="/"> <xsl:for-each select="parents/parent"> .... <img id="ImgChildren" name="ImgChildren" ........> <xsl:attribute name="ChildrenImg"> <xsl:for-each select="children/child"> <xsl:copy-of select="children/child/node()" /> </xsl:for-each> </xsl:attribute> .... May anyone help me, please?? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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