RE: [xsl] transforming to breaks

Subject: RE: [xsl] transforming to breaks
From: "Koes, Derrick" <Derrick.Koes@xxxxxxxxxxxxxxxx>
Date: Tue, 25 Mar 2003 11:31:40 -0500
Thanks Jarno!

-----Original Message-----
From: Jarno.Elovirta@xxxxxxxxx [mailto:Jarno.Elovirta@xxxxxxxxx] 
Sent: Tuesday, March 25, 2003 10:34 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] transforming to breaks

> I have a node like <nodeName>blah blah&#13;&#10;more blah 
> blah</nodeName>.
> I wish to transform this to html, using <BR></BR> for the carriage
> return/linefeed combo.
> How can I do this?

Recursive template, e.g.

template "changer"
  param "text"
    when contains($text, "&#xA;")
      value-of substring-before($text, "&#xA;")
      call-template "changer>
        with-param "text" substring-after($text, "&#xA;")
      value-of $text

The XML parser changes &#13;&#10; sequences into single &#10;, so you just
need to change LINE FEED characters.


Jarno - Linnunradan käsikirja liftareille: Osa 14

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