[xsl] Re: node concatenation

["Dimitre Novatchev" <dnovatchev@xxxxxxxxx>]

Hi bix,

Just use the Muenchian method.

This transformation:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:key name="kEl" match="element" use="@name"/>

 <xsl:key name="kAttr" match="attribute"
          use="concat(../@name, '|', @name)"/>

 <xsl:key name="kchEl" match="element"
          use="concat(../@name, '|', @name)"/>

  <xsl:template match="/">
    <els>
      <xsl:for-each
       select="//element[generate-id()
                         =
                          generate-id(key('kEl', @name)[1])
                          ]">
        <element name="{@name}">
          <xsl:for-each
           select="//attribute[generate-id()
                              =
                               generate-id(key('kAttr',
                                               concat(current()/@name,
                                                      '|',
                                                       @name
                                                      )
                                               )[1]
                                           )
                               ]">
            <attribute name="{@name}"/>
          </xsl:for-each>
          <xsl:for-each
           select="//element[generate-id()
                              =
                               generate-id(key('kchEl',
                                               concat(current()/@name,
                                                      '|',
                                                       @name
                                                      )
                                               )[1]
                                           )
                               ]">
            <elementRef  name="{@name}"/>
          </xsl:for-each>
        </element>
      </xsl:for-each>
    </els>
  </xsl:template>
</xsl:stylesheet>


when applied on your source.xml:

<els>
  <element name="a">
    <attribute name="attA1"/>
    <attribute name="attA2"/>
    <element name="aa">
      <attribute name="attAA1"/>
      <attribute name="attAA2"/>
    </element>
  </element>
  <element name="b" />
  <element name="a">
    <attribute name="attA3"/>
    <attribute name="attA4"/>
    <element name="ab">
      <attribute name="attAB1"/>
      <attribute name="attAB2"/>
      <element name="aba">
        <attribute name="attABA1"/>
        <attribute name="attABA2"/>
        <attribute name="attABA3"/>
        <attribute name="attABA4"/>
      </element>
    </element>
  </element>
  <element name="a"/>
  <element name="b">
    <element name="ba"/></element>
</els>

Produces the wanted result:

<els>
   <element name="a">
      <attribute name="attA1"/>
      <attribute name="attA2"/>
      <attribute name="attA3"/>
      <attribute name="attA4"/>
      <elementRef name="aa"/>
      <elementRef name="ab"/>
   </element>
   <element name="aa">
      <attribute name="attAA1"/>
      <attribute name="attAA2"/>
   </element>
   <element name="b">
      <elementRef name="ba"/>
   </element>
   <element name="ab">
      <attribute name="attAB1"/>
      <attribute name="attAB2"/>
      <elementRef name="aba"/>
   </element>
   <element name="aba">
      <attribute name="attABA1"/>
      <attribute name="attABA2"/>
      <attribute name="attABA3"/>
      <attribute name="attABA4"/>
   </element>
   <element name="ba"/>
</els>


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL


"bix xslt" <bix_xslt@xxxxxxxxxxx> wrote in message
news:F140yqZchMExMrLveu700037520@xxxxxxxxxxxxxx
> All,
>
> I believe this may have been covered before with some of the grouping
q/a's
> but I did a few searches both on the fact and the archive, and I was
unable
> to find what I was looking for.
>
> Essentially, I've got something similar to the following:
> ~~~~xml fragment~~~~
> <element name="a">
>   <attribute name="attA1"/>
>   <attribute name="attA2"/>
>   <element name="aa">
>     <attribute name="attAA1"/>
>     <attribute name="attAA2"/>
>   </element>
> </element>
> <element name="b" />
> <element name="a">
>   <attribute name="attA3"/>
>   <attribute name="attA4"/>
>   <element name="ab">
>     <attribute name="attAB1"/>
>     <attribute name="attAB2"/>
>     <element name="aba">
>       <attribute name="attABA1"/>
>       <attribute name="attABA2"/>
>       <attribute name="attABA3"/>
>       <attribute name="attABA4"/>
>     </element>
>   </element>
> </element>
> <element name="a"/>
> <element name="b">
>   <element name="ba"/>
> </element>
>
> I would like to combine all of the similar elements and reference the
> element children into something like this:
> ~~~ xml fragment output ~~~
> <element name="a">
>   <attribute name="attA1"/>
>   <attribute name="attA2"/>
>   <attribute name="attA3"/>
>   <attribute name="attA4"/>
>   <elementRef name="aa"/>
>   <elementRef name="ab"/>
> </element>
> <element name="b">
>   <elementRef name="ba"/>
> </element>
> <element name="aa">
>   <attribute name="attAA1"/>
>   <attribute name="attAA2"/>
> </element>
> <element name="ab">
>   <attribute name="attAB1"/>
>   <attribute name="attAB2"/>
>   <elementRef name="aba">
> </element>
> ....etc
>
> I am attempting to come up with an automated way of storing off what the
DTD
> is of the xml data produced by my database.  My hope is that I can
transform
> my original xml into this newer format (element/attribute), and then
> transform that into a DTD file.  I have an xsl file that works through all
> of the original xml data and produces what you see above.  However, I'm at
a
> loss how to group/concatenate the multiple data outputs.  If there is a
> better way to do this, I'd sure appreciate the help.
>
> Thanks!
> bix
>
>
>
>
>
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