Subject: RE: [xsl] Parameterized sort From: TSchutzerWeissmann@xxxxxxxxxxxxxxxx Date: Tue, 1 Apr 2003 15:00:35 +0100 |
Hi Kim, [...] > I know that the sort key if > defined as > parameter, I should use "xalan:evalue($sortKey)" or "*[name() > = $sortKey]". > In this case, I want to sort the rows by the FirstName column > or by LastName > column and First Name. You don't need the evalue function, or name() here. > If I say, > <xsl:sort select="column[@name='FirstName']"/> > then, it works properly. so just use <xsl:sort select="column[@name=$sortKey]"/> where $sortKey contains either "FirstName" or "LastName". You've given the columns @name attributes, so you don't need the name() function. On the other hand, if you had <row> <columnA>foo</columnA> <columnB>bar</columnB> </row> and you wanted to sort either on columnA or columnB, you'd use <xsl:sort select="*[name()=$sortKey]"/> HTH, Tom SW XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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