[xsl] Listing things in columns

[walter.crockett@xxxxxxxxxxxxxxxxxxxxx]

Because I am working with database meta data (tables and columns), this
question could get confusing, so I will change my objects to Crates and
Oranges. I need to list all the Oranges in a Crate, and hyperlink from the
name of each Orange in the list to a table that contains information that
describes the Orange. 

Each Crate may have from 1 to more than 100 Oranges. When I list them
alphabetically, in paragraph form, the code looks like this:

<xsl:for-each
select="//Object[@id=$CrateID]/Relationships/Relationship[Name='Has_Orange']
/ValueList/Value/Reference">
	<xsl:sort select="." data-type="text" order="ascending"/>
	<xsl:variable name="OrangeName" select="."/>
	<xsl:variable name="OrangeID" select="./@Id"/>
	<a href="{$OrangeID}"><xsl:value-of select="$OrangeName"/></a>	
	<xsl:if test="position() != last()">, </xsl:if>
</xsl:for-each>

But this is messy. Instead, I would like to list them in three columns side
by side. 

I tried the following:
<table>
 <tr>
  <xsl:for-each
select="//Object[@id=$CrateID]/Relationships/Relationship[Name='Has_Orange']
/ValueList/Value/Reference">
    <xsl:variable name="OrangeName" select="."/>
    <xsl:variable name="OrangeID" select="./@Id"/>
    <td>
	<a href="{$OrangeID}"><xsl:value-of select="$OrangeName"/></a>
    </td>
    <xsl:if test="position() mod 3 = 0"> [something here to end a row and
start a new row]</xsl:if>
  </xsl:for-each>
 </tr>
</table>

But I couldn't make anything work inside the if test, because it doesn't
like to see </tr><tr>.

Is this a ridiculous way to go about it? Any suggestions?

Walter Crockett

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