Subject: RE: [xsl] Newbie Q: Why are element contents being passed through? From: "Passin, Tom" <tpassin@xxxxxxxxxxxx> Date: Thu, 10 Apr 2003 10:28:10 -0400 |
[Elijah Mori] > I have an xml source doc which I want to turn into an xhtml document > with a form, inputs, labels and so forth. What is happening > is that the > contents of the elements in the xml document are turning up in the > output and I can't understand why. I have simplified the xml > and the xsl > until there is almost nothing happening, and the element > contents still > come through. > I hope that your xml sample is not what you actually tested, because it is not well-formed. Assuming that the missing "</input>' has been restored, you are seeing the results of the build-in default template getting applied. This is happening in the template matching "form". You have <xsl:apply-templates/> in there, but there are no templates that match anything. The processor therefore applies the built-in template, which just gets the text content of the elements it operates on. You canverify this behavior by supplying a template that matches any element and does nothing: <xsl:apply-templates match='*'/> However, this is probably not what you want because you want to process the child elements of the form. You probably were thinking of using xsl:copy-of, but you better not because your input document does not contain proper html form elements. You have <input type='select'>..., bu it is supposed to be a <select .... ...> element instead. You could write a template to make this change or you could change the source format. Cheers, Tom P XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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