Subject: Re: [xsl] why doesn't 'self::NODE' work? From: "James J. Ramsey" <jjramsey_6x9eq42@xxxxxxxxx> Date: Mon, 14 Apr 2003 18:55:15 -0700 (PDT) |
--- "Wright, Steve" <Steve.Wright@xxxxxxx> wrote: > <xsl:template match="PARA/LINK"> > <xsl:value-of select="self::LINK" /> > </xsl:template> As far as I understand, <xsl:value-of select="foo-element"/> will not have a predictable (or usable) result if foo-element has children. What you need to do is <xsl:template match="PARA/LINK"> <xsl:apply-templates/> </xsl:template> and create templates for handling the children of LINK, FIG, and TTL, maybe something like: <xsl:template match="PARA/LINK/FIG"> <!-- Something to display the figure --> <xsl:apply-templates select="TTL"/> </xsl:template> <xsl:template match="PARA/LINK/FIG/TTL"> <!-- AFAIK, this is enough to return the contents of TTL. --> <xsl:apply-templates/> </xsl:template> I used "PARA/LINK/FIG" and "PARA/LINK/FIG/TTL" because I wasn't sure if TTL and FIG were also used as the names of children of other elements, and perhaps had subtly different representations in those contexts. __________________________________________________ Do you Yahoo!? The New Yahoo! Search - Faster. Easier. Bingo http://search.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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