Subject: Re: [xsl] xsl:if giving me "Invalid type" error From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 15 Apr 2003 20:15:36 +0100 |
<xsl:variable name="firstDiv"> <xsl copy-of select="(div[1]|div0[1]|div1[1]|divGen[1])[1]"/> </xsl:variable> No that's a result-tree-fragment which isn't much more use than a string for what you want. You dont't want a copy-of the first div anyway you want the real thing. <xsl:variable name="firstDiv" select="(div[1]|div0[1]|div1[1]|divGen[1])[1]"/> That variable does contain a node set. David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] xsl:if giving me "Invalid, James J. Ramsey | Thread | Re: [xsl] xsl:if giving me "Invalid, James J. Ramsey |
RE: [xsl] more on Using apply-templ, Kathy Burke | Date | Re: [xsl] xsl:if giving me "Invalid, James J. Ramsey |
Month |