How can I get the value of schemaLocation from the xsd:element/@ref
attribute in the following XML Schema sample:
...
<xsd:schema ... xmlns:xxx="http://www.yo.com/example.namespace";>
<xsd:import namespace="http://www.yo.com/example.namespace";
schemaLocation="http://www.yo.com/example.xsd"/>
...
<xsd:element ref="xxx:SomeName"/>
...
My xsl looks something like this:
...
<xsl:template match="xsd:element[@ref]">
<xsl:element name="{@ref}">
<xsl:variable name="schema"
select="//xsd:import/@schemaLocation[../@namespace=???]"/>
<xsl:apply-templates
select="document($schema)//element[@name=current()/@ref]"/>
</xsl:element>
</xsl:template>
...
Am I on the right track? If so, what should replace the ??? in the
location path? If I remove the stuff between the xsl:element tags I get
the following output:
...
<xxx:SomeName xmlns:xxx="http://www.yo.com/example.namespace"/>
...
So XSLT knows the namespace I want...I just don't know how to ask it.
Thanks.
BTW...I'm using LibXSLT and perl for the transform.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list