Subject: AW: [xsl] Vertical table display with sort From: "Zink, Juergen" <Juergen.Zink@xxxxxxxxxxxxxxxxxxxx> Date: Wed, 30 Apr 2003 14:00:40 +0200 |
Hi, <snip> The problem is I don't know the object name. (like hereyougo) <snip> Ok. From the first element with which has elements with attribut displayposition select all elements with attribut displayposition. <xsl:key name="displayposition" match="*[@displayposition]" use="@displayposition"/> <xsl:template match="/"> <table> <xsl:for-each select="o/com/*[*/@displayposition][1]/*[@displayposition]"> <xsl:sort select="@displayposition"/> <tr> <th><xsl:value-of select="@displayname"/></th> <xsl:for-each select="key('displayposition', @displayposition)" > <td><xsl:value-of select="." /></td> </xsl:for-each> </tr> </xsl:for-each> </table> </xsl:template> Cheers, Juergen XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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